2x+2+2(x-1)^1/2=16

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Solution for 2x+2+2(x-1)^1/2=16 equation: 



2x+2+2(x-1)^1/2=16

We move all terms to the left:

2x+2+2(x-1)^1/2-(16)=0

We add all the numbers together, and all the variables

2x+2(x-1)^1/2-14=0

We multiply all the terms by the denominator


2x*2+2(x-1)^1-14*2=0

We add all the numbers together, and all the variables

2x*2+2(x-1)^1-28=0

Wy multiply elements

4x+2(x-1)^1-28=0

We move all terms containing x to the left, all other terms to the right

4x+2(x-1)^1=28

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